-10x+8=9x^2-11x

Solution for -10x+8=9x^2-11x equation:

-10x+8=9x^2-11x

We move all terms to the left:

-10x+8-(9x^2-11x)=0

We get rid of parentheses

-9x^2-10x+11x+8=0

We add all the numbers together, and all the variables

-9x^2+x+8=0

a = -9; b = 1; c = +8;
Δ = b2-4ac
Δ = 12-4·(-9)·8
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-17}{2*-9}=\frac{-18}{-18}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+17}{2*-9}=\frac{16}{-18}
=-8/9
$